Algorithm, Program & Output for Sum of factors of a number

Algorithm

1. Start
2. Read a number ‘n’ > 0
3. Assign sum with 0, i with 1
4. If i<=n then repeat steps (5) and (6) else go to (7)
5. If modulus(n,i) = 0

then sum ß sum + i and go to (6)

else go to (6)

6. i ß i + 1
7. Print sum of factors of n is sum
8. Stop

 Program

#include <stdio.h>

main()

{

            int n,i,sum ;

            clrscr() ;

            printf("\tProgram to find Sum of factors of a Number\n") ;

            printf("\n  Input\n\n") ;

            printf("Enter a Number : ") ;

            scanf("%d",&n) ;

            sum = 0 ;

            for (i=1;i<=n;i++)

                if ((n%i) == 0)

                        sum += i ;

            printf("\n  Output\n\n") ;

            if (n <= 0)

                        printf("Enter greater than Zero") ;

            else

                        printf("Sum of factors of %d is : %d",n,sum) ;

            getch() ;

}

Output

Program to find Sum of factors of a Number

  Input

Enter a Number : 36

  Output

Sum of factors of 36 is : 91

Program to find Sum of factors of a Number

  Input

Enter a Number : 0

  Output

Enter greater than Zero