Algorithm, Program & Output for Sum of digits of a number

Algorithm

1. Start
2. Read a number ‘n’
3. Assign m with n, sum with 0
4. If n ≠ 0 repeat steps (5) thru (7) else go to (8)
5. k ß modulus(n,10)
6. sum ß sum + k
7. n ß quotient of n/10
8. Print sum of digits of n is sum
9. Stop

Program

#include <stdio.h>

main()

{

            int n,m,k,sum ;

            clrscr() ;

            printf("\tProgram to find Sum of Digits of a Number\n") ;

            printf("\n  Input\n\n") ;

            printf("Enter a Number : ") ;

            scanf("%d",&n) ;

            m = n ;

            sum = 0 ;

            while (n != 0)

              {

                  k = n%10 ;

                  sum += k ;

                  n = n/10 ;

              }

            printf("\n  Output\n\n") ;

            printf("Sum of Digits of %d is : %d",m,sum) ;

            getch() ;

}

Output

     Program to find Sum of Digits of a Number

  Input

Enter a Number : 1729

  Output

Sum of Digits of 1729 is : 19

       Program to find Sum of Digits of a Number

  Input

Enter a Number : -786

  Output

Sum of Digits of -786 is : -21